Hey Rodney, This was asked last spring, I believe this formula is right... http://www.satobs.org/seesat/Feb-2005/0231.html Regards, Jeff Umbarger Plano, TX USA --- Rodney Austin <rodcomet@gmail.com> wrote: > Hi All, > Probably a stupid question, but is there a > note somewhere that > will tell me how to compute the apparent declination > of the > geostationary belt from my latitude (-39 degrees)? > Some years ago I > recall seeing something about it in Sky & Telescope, > and of course I > could probably work it out by simple trigonometry. > Sorry I'm a bit > lazy. I'm not after any particular satellite, just a > generalisation. > From here it should be north of the celestial > equator I think, with a > rough guess of dec +5 degrees? Thanks for any help. > Sorry to be a bother. > Cheers > Rod Austin > > ------------------------------------------------------------------------- > Subscribe/Unsubscribe info, Frequently Asked > Questions, SeeSat-L archive: > http://www.satobs.org/seesat/seesatindex.html > > ------------------------------------------------------------------------- Subscribe/Unsubscribe info, Frequently Asked Questions, SeeSat-L archive: http://www.satobs.org/seesat/seesatindex.html
This archive was generated by hypermail 2b29 : Mon Oct 17 2005 - 01:09:36 EDT